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-4.9x^2+0.6x+1=0
a = -4.9; b = 0.6; c = +1;
Δ = b2-4ac
Δ = 0.62-4·(-4.9)·1
Δ = 19.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{19.96}}{2*-4.9}=\frac{-0.6-\sqrt{19.96}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{19.96}}{2*-4.9}=\frac{-0.6+\sqrt{19.96}}{-9.8} $
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